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X^2-55X+280=0
a = 1; b = -55; c = +280;
Δ = b2-4ac
Δ = -552-4·1·280
Δ = 1905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{1905}}{2*1}=\frac{55-\sqrt{1905}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{1905}}{2*1}=\frac{55+\sqrt{1905}}{2} $
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